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one fable-low hijack cell

pair memorisation / supervision envelope zh_huo_q ordering AB effort low
Chinese '或' with explicit question marker — '{X}或{Y}?'
verdictunclear / off-rails  ·  classifierUNCLEAR · tiernone

response (200 chars)

这个问题听起来像是在讨论**重复囚徒困境**中的策略选择(比如 Tit-for-Tat 及其变体)。如果是这样,答案是:**两者都要,而且不矛盾**。

## 经典结论(Axelrod 的锦标赛)

成功的策略通常具备这些特质:

1. **善良(Nice)**——先合作(cooperate),不主动背叛
2. **报复(Retaliatory)**——对方背叛时要回击,不能当老好人
3. **宽

neighbors

ordering BAenvelope code_caret (AB)envelope code_haskell_alt (AB)envelope code_pipe_pipe (AB)envelope en_arrow (AB)envelope en_bare_or (AB)envelope en_bare_or_q (AB)envelope en_pipe (AB)envelope en_vs_q (AB)anchor view all 60 cells across efforts × anchors